C语言 | Leetcode C语言题解之第132题分割回文串II

题目：

题解：

int minCut(char* s) {int n = strlen(s);bool g[n][n];memset(g, 1, sizeof(g));for (int i = n - 1; i >= 0; --i) {for (int j = i + 1; j < n; ++j) {g[i][j] = (s[i] == s[j]) && g[i + 1][j - 1];}}int f[n];for (int i = 0; i < n; ++i) {f[i] = INT_MAX;}for (int i = 0; i < n; ++i) {if (g[0][i]) {f[i] = 0;} else {for (int j = 0; j < i; ++j) {if (g[j + 1][i]) {f[i] = fmin(f[i], f[j] + 1);}}}}return f[n - 1];
}