Leetcode 347. 前 K 个高频元素

解法： 字典统计排序

class Solution:def topKFrequent(self, nums: List[int], k: int) -> List[int]:cont = {}for eve in nums:if eve not in cont:  cont[eve] = 1else: cont[eve] += 1contlist = sorted(cont.items(), key=lambda x: x[1])res = [eve[0] for eve in contlist]return res[-k:]