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scala 身份证号码

2025/2/24 21:30:55 来源:https://blog.csdn.net/2401_87373448/article/details/144336908  浏览:    关键词:scala 身份证号码

根据身份证号码查询该持卡人的籍贯

object Test_身份证查询籍贯 {
  def main(args: Array[String]): Unit = {
    val code = "42005200210030051".substring(0,2)
    println(code)
    //判断42是哪个省的
    //湖北
//    if(code == "42"){
//      println("42对应省份为:湖北")
//    }else if(code =="33"){
//      println("浙江")
//    }else{
//      println()
//    }
 
    val province = code match {
      case "11" => "北京"
      case "12" => "天津"
      case "13" => "河北"
      case "14" => "山西"
      case "15" => "内蒙古"
      case "21" => "辽宁"
      case "22" => "吉林"
      case "23" => "黑龙江"
      case "31" => "上海"
      case "32" => "上海"
      case "33" => "浙江"
      case "34" => "安徽"
      case "35" => "福建"
      case "36" => "江西"
      case "37" => "山东"
      case "41" => "河南"
      case "42" => "湖北"
      case "43" => "湖南"
      case "44" => "广东"
      case "45" => "广西"
      case "46" => "海南"
      case "50" => "重庆"
      case "51" => "四川"
      case "52" => "贵州"
      case "53" => "云南"
      case "54" => "西藏"
      case "61" => "陕西"
      case "62" => "甘肃"
      case "63" => "青海"
      case "64" => "宁夏"
      case "65" => "新疆"
      case "71" => "台湾"
      case "81" => "香港"
      case "82" => "澳门"
      case "91" => "国外"
      case "_" => "未知"
    }
    println(province)
  }
}

根据1,2,3,4,5,6,7 --> 对应 的星期的英文

 val code1=6
    val day =code1 match {
      case 1 => "monday"
      case 2 => "tuesday"
      case 3 => "wednesday"
      case 4 => "thursday"
      case 5 => "friday"
      case 6 => "saturday"
      case 7 => "sunday"
 
      case _=>"该星期数不存在"
    }
    println(day)
 val m1 =Map((1,"monday"),(2,"tuesday"),(3,"wednesday"),(4,"thursday"),(5,"friday"),(6,"saturday"),(7,"sunday"))
    println(m1(30))
 val t0 =(3)
    val t1 =(2,3)
    val t2 =(2,3,4)
    //P220
    //求长方形,梯形,正方形的面积
    def patterTuple(x:Any) =x match {
      case (a) =>println("正方形的面积")
      case (a,b) =>println("长方形的面积")
      case (a,b,c) =>println(s"梯形面积${a}")
      case _ => println("未知")
    }
    patterTuple(t0)
    patterTuple(t1)
    patterTuple(t2)

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