C语言钥匙迷宫2.0

开头

大家好，我叫这是我58。废话不多说，咱们直接开始。

程序

#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
#include <string.h>
#include <Windows.h>
enum color {Y,B,R
};
typedef struct Key {enum color co;int ix;int iy;
}Key;
typedef struct Door {enum color co;int ix;int iy;
}Door;
void printmaze(char strmaze[11][11], int* apkeys, Key(*k)[12], Door(*d)[29]) {const char sarr[3][5] = { "33","36","31;1" };Key* ka = *k;Door* da = *d;const Key* const kb = *k + 11;const Door* const db = *d + 28;int ia = 0;int ib = 0;char stc[5] = "";for (ia = 0; ia < 11; ia++) {for (ib = 0; ib < 11; ib++) {while (ka->ix <= ia) {if (ka->iy == ib && ka->ix == ia) {strcpy(stc, sarr[ka->co]);}if (ka == kb) { break; }ka++;}while (da->ix <= ia) {if (da->iy == ib && da->ix == ia) {strcpy(stc, sarr[da->co]);}if (da == db) {break;}da++;}printf("\033[%sm%c\033[0m", 'G' == strmaze[ia][ib] ? "32;1" : !!strcmp(stc,"33") + !!strcmp(stc,"36") + !!strcmp(stc,"31;1") == 2 && 'P' != strmaze[ia][ib] && '*' != strmaze[ia][ib] ? stc : "0", strmaze[ia][ib]);ka = *k;da = *d;strcpy(stc, "");}printf("|\n");}printf("-----------@\n\033[33m黄钥匙*%d\033[0m\n\033[36m蓝钥匙*%d\033[0m\n\033[31;1m红钥匙*%d\033[0m\n", apkeys[0], apkeys[1], apkeys[2]);
}
int main() {int apkeys[3] = { 0 };Key k[12] = { {R,0,5},{Y,0,6},{B,0,8},{R,2,3},{B,3,4},{B,3,6},{Y,4,3},{R,4,7},{Y,6,3},{Y,6,4},{Y,7,1},{Y,9,0} };Door d[29] = { {B,0,7}, {Y,0,10}, {Y,1,0}, {B,1,1}, {R,1,3}, {B,1,6}, {Y,1,9}, {B,1,10}, {B,2,9}, {Y,3,0}, {Y,4,8}, {Y,5,0}, {Y,7,7}, {Y,7,8}, {B,7,9}, {Y,7,10}, {Y,8,0}, {R,8,5}, {Y,8,7}, {R,8,8}, {B,8,9}, {B,8,10}, {B,9,7}, {B,9,8}, {R,9,9}, {R,9,10}, {Y,10,7}, {B,10,8}, {R,10,9} };const Key ka[12] = { {R,0,5},{Y,0,6},{B,0,8},{R,2,3},{B,3,4},{B,3,6},{Y,4,3},{R,4,7},{Y,6,3},{Y,6,4},{Y,7,1},{Y,9,0} };const Door da[29]= { {B,0,7}, {Y,0,10}, {Y,1,0}, {B,1,1}, {R,1,3}, {B,1,6}, {Y,1,9}, {B,1,10}, {B,2,9}, {Y,3,0}, {Y,4,8}, {Y,5,0}, {Y,7,7}, {Y,7,8}, {B,7,9}, {Y,7,10}, {Y,8,0}, {R,8,5}, {Y,8,7}, {R,8,8}, {B,8,9}, {B,8,10}, {B,9,7}, {B,9,8}, {R,9,9}, {R,9,10}, {Y,10,7}, {B,10,8}, {R,10,9} };int i = 0;int ia = 0;char ch = 0;char strmaze[11][11] = {' ',' ',' ',' ','*','+','+','#','+',' ','#','#','#','*','#','*','*','#',' ',' ','#','#',' ',' ','*','+',' ','*','*','*','*','#',' ','#',' ','*',' ','+','*','+',' ','*','*',' ',' ',' ','*','+',' ','*',' ','+','#',' ',' ','#','*','*','*','*','*','*','*','*','*',' ',' ',' ','*','+','+','*',' ',' ',' ',' ',' ',' ','+','*','*',' ','*',' ','#','#','#','#','#',' ',' ','*',' ','#',' ','#','#','#','#','+','*',' ','*','*',' ',' ','#','#','#','#','P','*',' ',' ',' ',' ',' ','#','#','#','G'};const char strmz[] = "    *++#+ ###*#**#  ##  *+ ****# # * +*+ **   *+ * +#  #*********   *++*      +** * #####  * # ####+* **  ####P*     ###G";char* cp = &strmaze[10][0];printf("欢迎你来玩这个\033[33m钥\033[36m匙\033[31;1m迷宫\033[0m，这个迷宫的规则与50层魔塔的规则基本无异，只不过输入“r”可以使你重新开始这个游戏，而且，这三种颜色的“+”：“\033[33m+\033[0m”“\033[36m+\033[0m”“\033[31;1m+\033[0m”分别代表了50层魔塔里的\033[33m黄钥匙\033[0m，\033[36m蓝钥匙\033[0m和\033[31;1m红钥匙\033[0m，并且那三种颜色的“#”：“\033[33m#\033[0m”“\033[36m#\033[0m”“\033[31;1m#\033[0m”分别代表了50层魔塔里的\033[33m黄门\033[0m，\033[36m蓝门\033[0m和\033[31;1m红门\033[0m，你明白了吗?");Sleep(6600);system("cls");while ('G' == strmaze[10][10]) {int ix = (cp - &strmaze[0][0]) / 11;int iy = (cp - &strmaze[0][0]) % 11;for (ia = 0; ia < 12; ia++) {if (k[ia].ix == ix && k[ia].iy == iy && -2 != k[ia].ix + k[ia].iy) {apkeys[k[ia].co]++;k[ia].ix = -1;k[ia].iy = -1;}}printmaze(strmaze, apkeys, &k, &d);scanf("%c", &ch);while ('\n' != getchar()) {;}*cp = ' ';switch (ch) {case 'w':for (i = 0; i < 11; i++) {if (cp == &strmaze[0][i]) {break;}}(11 == i && '*' != *(cp - 11) && '#' != *(cp - 11)) && (cp -= 11);for (ia = 0; ia < 29; ia++) {if (apkeys[d[ia].co] > 0 && -1 != d[ia].ix && -1 != d[ia].iy && d[ia].ix == ix - 1 && d[ia].iy == iy) {strmaze[d[ia].ix][d[ia].iy] = ' ';apkeys[d[ia].co]--;d[ia].ix = -1;d[ia].iy = -1;}}break;case 'a':for (i = 0; i < 11; i++) {if (cp == &strmaze[i][0]) {break;}}(11 == i && '*' != *(cp - 1) && '#' != *(cp - 1)) && cp--;for (ia = 0; ia < 29; ia++) {if (apkeys[d[ia].co] > 0 && -1 != d[ia].ix && -1 != d[ia].iy && d[ia].ix == ix && d[ia].iy == iy - 1) {strmaze[d[ia].ix][d[ia].iy] = ' ';apkeys[d[ia].co]--;d[ia].ix = -1;d[ia].iy = -1;}}break;case 's':for (i = 0; i < 11; i++) {if (cp == &strmaze[10][i]) {break;}}(11 == i && '*' != *(cp + 11) && '#' != *(cp + 11)) && (cp += 11);for (ia = 0; ia < 29; ia++) {if (apkeys[d[ia].co] > 0 && -1 != d[ia].ix && -1 != d[ia].iy && d[ia].ix == ix + 1 && d[ia].iy == iy) {strmaze[d[ia].ix][d[ia].iy] = ' ';apkeys[d[ia].co]--;d[ia].ix = -1;d[ia].iy = -1;}}break;case 'd':for (i = 0; i < 11; i++) {if (cp == &strmaze[i][10]) {break;}}(11 == i && '*' != *(cp + 1) && '#' != *(cp + 1)) && cp++;for (ia = 0; ia < 29; ia++) {if (apkeys[d[ia].co] > 0 && -1 != d[ia].ix && -1 != d[ia].iy && d[ia].ix == ix && d[ia].iy == iy + 1) {strmaze[d[ia].ix][d[ia].iy] = ' ';apkeys[d[ia].co]--;d[ia].ix = -1;d[ia].iy = -1;}}break;case 'r':for (ia = 0; ia < 12; ia++) {k[ia] = ka[ia];d[ia] = da[ia];}for (; ia < 29; ia++) {d[ia] = da[ia];}for (i = 0; i < 121; i++) {strmaze[0][i] = strmz[i];}cp = &strmaze[10][0];for (i = 0; i < 3; i++) {apkeys[i] = 0;}break;default:break;}*cp = 'P';system("cls");}system("color 0A");printf("恭喜你，你赢了\n");return 0;
}

程序的流程图

程序游玩的效果

结尾

在你看到这里之后，可以评论来互动一下我哦。