【电机控制器】ESP32-C3语言模型——豆包

2025/2/22 13:34:52 来源：https://blog.csdn.net/qq_42681425/article/details/145779865 浏览: 次关键词：【电机控制器】ESP32-C3语言模型——豆包

【电机控制器】ESP32-C3语言模型——豆包

文章目录

@[TOC](文章目录)

前言
一、简介
二、代码
三、实验结果
四、参考资料
总结

前言

使用工具：

提示：以下是本篇文章正文内容，下面案例可供参考

一、简介

二、代码

#include <WiFi.h>
#include <HTTPClient.h>
#include <ArduinoJson.h>// 1. Replace with your network credentials
const char* ssid = "你需要改的地方";
const char* password = "你需要改的地方";// 2. Replace with your OpenAI API key
const char* doubao_apiKey = "你需要改的地方";// Send request to OpenAI API
String inputText = "你好，豆包！";
String apiUrl = "https://ark.cn-beijing.volces.com/api/v3/chat/completions";String answer;
String getGPTAnswer(String inputText) {HTTPClient http;http.setTimeout(20000);http.begin(apiUrl);http.addHeader("Content-Type", "application/json");String token_key = String("Bearer ") + doubao_apiKey;http.addHeader("Authorization", token_key);String payload = "{\"model\":\"你需要改的地方\",\"messages\":[{\"role\":\"system\",\"content\":\"你是我的AI助手vor，你必须用中文回答且字数不超过85个\"},{\"role\":\"user\",\"content\":\"" + inputText + "\"}],\"temperature\": 0.3}";int httpResponseCode = http.POST(payload);if (httpResponseCode == 200) {String response = http.getString();http.end();Serial.println(response);// Parse JSON responseDynamicJsonDocument jsonDoc(1024);deserializeJson(jsonDoc, response);String outputText = jsonDoc["choices"][0]["message"]["content"];return outputText;// Serial.println(outputText);} else {http.end();Serial.printf("Error %i \n", httpResponseCode);return "<error>";}
}void setup() {// Initialize SerialSerial.begin(115200);// Connect to Wi-Fi networkWiFi.mode(WIFI_STA);WiFi.begin(ssid, password);Serial.print("Connecting to WiFi ..");while (WiFi.status() != WL_CONNECTED) {Serial.print('.');delay(1000);}Serial.println(WiFi.localIP());answer = getGPTAnswer(inputText);Serial.println("Answer: " + answer);Serial.println("Enter a prompt:");
}void loop() {// do nothingif (Serial.available()) {inputText = Serial.readStringUntil('\r');  //  \r表示结束符为回车符// inputText.trim();Serial.println("\n Input:" + inputText);answer = getGPTAnswer(inputText);Serial.println("Answer: " + answer);Serial.println("Enter a prompt:");}// delay(2);
}