xpath模块
from lxml import etreestr1 = """
<div><ul><li class="item-0"><a href="link1.html">first item</a></li><li class="item-1"><a href="link2.html">second item</a></li><li class="item-inactive"><a href="link3.html"><span class="bold">third item</span></a></li><li class="item-1"><a href="link4.html">fourth item</a></li><li class="item-0"><a class="test" href="link5.html">fifth item</a>111</li><li class="item-0" vmid="10023898942">bsajkfhsdbfhjsdgbhfds</li></ul></div>
"""
# 将字符串转化为html对象
strTree1 = etree.HTML(str1)
print(strTree1.xpath('//li/text()')) #获取所有li里面的内容，这里只能获取直属li里面的内容
print(strTree1.xpath('//li/@class'))
# xpath中的下标，是从1开始的
print(strTree1.xpath('//li[3]/a/@href'))
# xpath中没有负数下标，若从右向左取，利用last获取最后一个 通过减一减二的方式获取倒数第二个倒数第三个
print(strTree1.xpath('//li[last()-1]/text()'))
# 获取指定属性值的标签
print(strTree1.xpath('//li[@class="item-1"]//text()'))
昵图网实例
from requests_html import HTMLSession
from lxml import etreesession = HTMLSession()
url = 'https://soso.nipic.com/?q=%E7%BE%8E%E5%A5%B3'response = session.get(url)
html = etree.HTML(response.text)imgNames = []
imgUrls = []
for i in range(1, 6):img_name = html.xpath(f'//ul[@id="img-list-outer"]/li[{i}]/a/img/@alt')img_url = html.xpath(f'//ul[@id="img-list-outer"]/li[{i}]/a/img/@data-original')imgNames.append(img_name[0])imgUrls.append('https:' + img_url[0])for i in range(len(imgUrls)):with open('美女\\' + imgNames[i] + '.jpg', 'wb') as f:f.write(session.get(imgUrls[i]).content) # content就是将响应转化为二进制内容
